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Chapter wise 1 jee

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chapter wise 1 JEE is a computer-based practice test for two chapters. The test is as per the latest pattern of JEE (Mains).

The Chapters included are.

  1. Some basic concepts in chemistry.
  2. Atomic Structure.
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Created by 390909fca797f6f55329353c0fa8a04bChemistry instructor

Chapter Wise 1 JEE

The Quiz is a JEE mains Level quiz containing 25 questions from Basic concepts, & Atomic structure.

In 25 questions 10 questions are single choice, 05 questions are Assertion reasons, 05 questions are match the following type, and 05 questions are integer type.

The time allotted for the quiz is 60 minutes.

The number of attempts remaining is 3

1 / 30

1. X’ is the amount of a substance that contains as many particles as there are atoms in exactly 12 g of the Y isotope. X and Y respectively are

2 / 30

2. Match the following type of rays given in Column I with their characteristics given in Column II. Select an appropriate answer from the codes given below.

MS31

3 / 30

3. Match the expressions/statements in Column I with expressions/Statements in Column II.

MS40

4 / 30

4. 29.2 % (w/w) HCl stock solution has a density of 1.25 g mL–1. The molecular weight of HCl is 36.5 g mol–1. Find the volume of (mL) of stock solution required to
prepare a 200 mL solution of 0.4 M HCl 

5 / 30

5. Statement 1: When two or more empty orbitals of equal energy are available. One electron must be placed in each until they are all half-filled.
Statement 2: The pairing of electron is an unfavorable phenomenon.

6 / 30

6. What is the work function of the metal, n the light of wavelength 4000 Å generates photoelectron of velocity 6 x 105 m s -1 from it? 
(Mass of electron = 9 x 10-31 kg, Velocity of light = 3 x 108 m s-1, Planck’s constant = 6.626 x 10-34 Js, Charge of electron = 1.6 x 10-19 JeV-1)

7 / 30

7. Statement 1: The principal quantum number, n, can have whole number values 1, 2, 3, … etc.
Statement 2: The angular momentum quantum number can never be equal to n.

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8. Match the entries in column I with the related entries in Column II

MS35

9 / 30

9. An element has mass number of 23 and its unipositive ion has electronic configuration 1s2 2s2 2p6. Select the correct statement(s).
(I) It is isotonic with Mg
24.
(II) The ratio of
n to l for last electron in atom of above element is 2.
(III) Atom of the above element is isoelectronic with H
2O.
(IV) Atom of the above element is paramagnetic.

10 / 30

10. The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about 9. The spectral series are

11 / 30

11. Arrange the following in the order of increasing mass (Atomic mass of O = 16, Cu = 63 and N = 14).
I. One atom of oxygen
II. One atom of nitrogen
III. 1 x 10
-10 mole of oxygen
IV. 1 x 10
-10 mole of copper

12 / 30

12. What is the concentration of sugar (C12H22O11mol L-1 if its 20 g are dissolved in enough water to make a final volume up to 2 L in mol L-1?

13 / 30

13. CH4 (g) + 2 O2 (g) → CO2 (g)+ 2H2O(g)
According to the above chemical reaction, following information have been given.
(i) One mole of CH4 (g) reacts with two moles of O2 (g)to give one mole of CO2 (g) and two moles of H2O(g)
(ii) One molecule of CH4 (g) reacts with 2 molecules of O2 (g) to give one molecule of CO2 (g) and 2 molecules of H2O(g)
(iii) 22.7 L of CH4 (g) reacts with 45.4 L of O2 (g) to give 22.7 L of CO2 (g) and 45.4 L of H2O(g)
(iv) 16 g of CH4 (g) reacts with 2 32 × g of O2 (g) to give 44 g of CO2 (g) and 2 18 × g of H2O(g)
From this information the correct interconversion should be

14 / 30

14. Match the expressions/statements in Column I with expressions/Statements in Column II.

MS38

15 / 30

15. The maximum number of electrons that can have principal quantum number, n = 3 and spin quantum number, ms =-1/2 is

16 / 30

Select the correct statement(s).
(I) Maximum number of electrons having
16. 12 s = +1/2 in Sulphur is 9.
(II) If electron has zero magnetic quantum number, then it must be present in
s-orbital.
(III) All isoelectronic ions have same value of
Zeff.
(IV) Number of subshell present in a
nth shell is equal to ‘n’.

17 / 30

17. Consider the following laws of chemical combination with examples.
I. Law of multiple proportion: N2O, NO, NO2.
II. Law of reciprocal proportion: H2O, SO2, H2S.
Which is correct with example?

18 / 30

18. What is the maximum number of electrons that may be present in all the atomic orbitals with principal quantum number 3 and azimuthal quantum number 2?

19 / 30

19. Which of the following has correct the matching of curve and orbital?

MS12

(I) I→ (2p); II→ (1s); III→ (4p)
(II) I→ (3
p); II→ (3d); III→ (3s)
(III) I→ (4
d); II→ (2p); III→ (5d)
(IV) I→ (2
s); II→ (4f); III→ (3d)

20 / 30

20. Find the value of n in the molecular formula BenAl2Si6O18

21 / 30

21. Mole fraction of the solute in a 1.00 molar aqueous solution is?

22 / 30

22. The first line in the Balmer series in the H-atom will have the frequency.

23 / 30

23. Silver (atomic weight = 108 g mol–1) has a density of 10.5 g cm–3. The number of silver atoms on a surface of area 10–12 m2 can be expressed in scientific notation as y x 10x. Find the value of x.

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24. Statement I: The ground state configuration of Cr is 3d5 4s1.
Statement II: A set of exactly half-filled orbitals containing parallel spin arrangement provide extra stability.

25 / 30

25. Statement I: p-orbital has dumb-bell shape. Because
Statement II: Electrons present in p-orbital can have one of three values for ‘m’, i.e., 0, +1, –1.

26 / 30

Consider the following statements about cathode rays.
I. These moves from cathode to anode.
II. These are visible rays.
III. Television picture tubes are cathode rays tubes.
IV. In the absence of electrical or magnetic field, these rays travel in a straight line.
26. Choose the correct statement from the above and mark the correct option.

27 / 30

27. Match the entries in column I with the related quantum number(s) in Column II

MS33

28 / 30

28. Statement 1: The Paschen series in the spectrum of hydrogen lies in the infra-red region.
Statement 2: The Paschen series is born of transition of electrons onto the second orbit from higher orbits.

29 / 30

29. Total number of atoms represented by the compound CuSO4. 5H2O is

30 / 30

30. Ethanol-water mixture has 46 g ethanol in 100 g mixture. By a suitable technique volatile component goes off. Thus

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