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Chapter wise 1 jee

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chapter wise 1 JEE is a computer-based practice test for two chapters. The test is as per the latest pattern of JEE (Mains).

The Chapters included are.

  1. Some basic concepts in chemistry.
  2. Atomic Structure.
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Created by 390909fca797f6f55329353c0fa8a04bChemistry instructor

Chapter Wise 1 JEE

The Quiz is a JEE mains Level quiz containing 25 questions from Basic concepts, & Atomic structure.

In 25 questions 10 questions are single choice, 05 questions are Assertion reasons, 05 questions are match the following type, and 05 questions are integer type.

The time allotted for the quiz is 60 minutes.

The number of attempts remaining is 3

1 / 30

1. A2 reacts with B2 in either of the following ways depending upon supply of B2:
A
2 + B2  2AB
A
2 + 3B2  2AB3
Also, the products formed may also react with appropriate reactant remaining to form other product. Using this information, match composition of the final mixture for initial amount of reactants.

MS36

2 / 30

2. Match the entries in column I with the related entries in Column II

MS35

3 / 30

3. 25 g of an unknown hydrocarbon upon burning produces 88 g of CO2 and 9 g of H2O. This unknown hydrocarbon contains.

4 / 30

4. Statement 1: The principal quantum number, n, can have whole number values 1, 2, 3, … etc.
Statement 2: The angular momentum quantum number can never be equal to n.

5 / 30

5. Statement 1: The Paschen series in the spectrum of hydrogen lies in the infra-red region.
Statement 2: The Paschen series is born of transition of electrons onto the second orbit from higher orbits.

6 / 30

6. What is the work function of the metal, n the light of wavelength 4000 Å generates photoelectron of velocity 6 x 105 m s -1 from it? 
(Mass of electron = 9 x 10-31 kg, Velocity of light = 3 x 108 m s-1, Planck’s constant = 6.626 x 10-34 Js, Charge of electron = 1.6 x 10-19 JeV-1)

7 / 30

7. Among the following, what is the number of elements showing only one non-zero oxidation state? O, Cl, F, N, P, Sn, Tl, Na, Ti

8 / 30

8. The probability density plots of 1s and 2s-orbitals are given in figure.

MS19

The density of dots in a region represents the probability density of finding electrons in the region. On the basis of above diagram, which of the following statements is incorrect?

 

9 / 30

9. Which of the following has correct the matching of curve and orbital?

MS12

(I) I→ (2p); II→ (1s); III→ (4p)
(II) I→ (3
p); II→ (3d); III→ (3s)
(III) I→ (4
d); II→ (2p); III→ (5d)
(IV) I→ (2
s); II→ (4f); III→ (3d)

10 / 30

10. Chlorine exists in two isotopic forms, Cl-37 and Cl-35 but its atomic mass is 35.5. This indicates the ratio of Cl-37 and Cl-35 is approximately.

11 / 30

11. The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about 9. The spectral series are

12 / 30

12. Calculate the mass of a photon with wavelength 3.6 Å.

13 / 30

13. When zinc reacts with dilute nitric acid, nitrous oxide is produced. What mass of the gas is evolved by treating 325 g zinc with excess of nitric acid?

14 / 30

14. Which of the following sets of quantum numbers are
correct?

MS17
The correct option is.

15 / 30

15. Match the following type of rays given in Column I with their characteristics given in Column II. Select an appropriate answer from the codes given below.

MS31

16 / 30

16. Arrange the following in the order of increasing mass (Atomic mass of O = 16, Cu = 63 and N = 14).
I. One atom of oxygen
II. One atom of nitrogen
III. 1 x 10
-10 mole of oxygen
IV. 1 x 10
-10 mole of copper

17 / 30

17. The maximum number of electrons that can have principal quantum number, n = 3 and spin quantum number, ms =-1/2 is

18 / 30

18. Total number of atoms represented by the compound CuSO4. 5H2O is

19 / 30

19. Similar to quantum number n, l, m a set of new quantum numbers was introduced with similar logic but different values defined as
x = 1, 2, 3... all (+ve) integral values
y = (x – 1) (x – 2)(x – 3)... No (–ve) value
z = +(y + 1/2) to – (y + 1/2) in integral steps
For each value of (
z), there will be two electrons, if (x + y) rule is followed similar to (n + l) rule then number of electrons in third shell for Zn (Atomic number = 30) is

20 / 30

20. Statement I: No two electrons in an atom can have the same values of four quantum numbers.
Statement II: No two electrons in an atom can be simultaneously in the same shell, same subshell, same orbitals and have the same spin.

21 / 30

21. Statement 1: When two or more empty orbitals of equal energy are available. One electron must be placed in each until they are all half-filled.
Statement 2: The pairing of electron is an unfavorable phenomenon.

22 / 30

22. Silver (atomic weight = 108 g mol–1) has a density of 10.5 g cm–3. The number of silver atoms on a surface of area 10–12 m2 can be expressed in scientific notation as y x 10x. Find the value of x.

23 / 30

Select the correct statement(s).
(I) Maximum number of electrons having
23. 12 s = +1/2 in Sulphur is 9.
(II) If electron has zero magnetic quantum number, then it must be present in
s-orbital.
(III) All isoelectronic ions have same value of
Zeff.
(IV) Number of subshell present in a
nth shell is equal to ‘n’.

24 / 30

24. Match the entries in column I with the related entries in Column II

MS34

25 / 30

25. Mole fraction of the solute in a 1.00 molar aqueous solution is?

26 / 30

26. Match the expressions/statements in Column I with expressions/Statements in Column II.

MS38

27 / 30

27. Statement I: p-orbital has dumb-bell shape. Because
Statement II: Electrons present in p-orbital can have one of three values for ‘m’, i.e., 0, +1, –1.

28 / 30

28. Consider the following laws of chemical combination with examples.
I. Law of multiple proportion: N2O, NO, NO2.
II. Law of reciprocal proportion: H2O, SO2, H2S.
Which is correct with example?

29 / 30

29. A student performs a titration with different burettes and finds titre values of 25.2 mL, 25.25 mL and 25.0 mL Find the number of significant figures in the average titre value

30 / 30

30. 29.2 % (w/w) HCl stock solution has a density of 1.25 g mL–1. The molecular weight of HCl is 36.5 g mol–1. Find the volume of (mL) of stock solution required to
prepare a 200 mL solution of 0.4 M HCl 

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